This week ’s puzzle puts you at the mercifulness of an unjust torturer . explain why he is unjust can help you make mother wit of a intimidating mathematical substantiation that last yr made headlines for being “ bigger than Wikipedia . ”

Illustration by Jim Cooke

We ’re out of the country for the next twosome of weeks , so the next two installment of the Sunday Puzzle will look a little different than normal . This calendar week , mathematicianJames Grime — who you may recognize fromsingingbanana , Numberphile , and elsewhere — has allow us to feature the video below , in which he use a mystifier to explain a mathematical validation . ( The television was recommended to us by Sunday Puzzle proofreader Aaron Baker — thanks Aaron ) Unlike previous newspaper column , where we ’ve presented the brainteaser one week and the answer the next , this workweek ’s puzzle is entirely self - contained ; in this video , Grime presents the puzzle and the solution all in one go . Next week ’s puzzle will , most likely , be similarly comprehensive in its presentation .

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Sunday Puzzle #32: Explaining A Wikipedia-Sized Proof

We ’ll be back next week with a fresh puzzle ( or teaser ! ) . Got a great brainteaser , original or otherwise , that you ’d like to see featured?E - mail me with your recommendations.(Be sure to include “ Sunday Puzzle ” in the subject line . )

SOLUTION To Sunday Puzzle #31: The Perilous Bridge Crossing

Last week I enquire you todetermine the little windowpane of time in which four people could cross a perilous bridge to rubber . The conditions of the puzzle were as follow :

https://gizmodo.com/how-quickly-can-you-cross-this-bridge-1703447829

The bridge can only support two people at once . The four people share one torch , which must be used to safely traverse the span . Each someone can baffle the bridge in a dissimilar amount of meter : Person A can thwart the bridge in one min , person B in two minutes , person C in five moment , and person D in ten instant . When two hoi polloi crossbreed together , they must do so at the slower person ’s pace .

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The most obvious solution to this puzzle is to have person A , who is the fastest , chaperone every other someone across the nosepiece , returning alone after each crossbreed with the torch in hand . By this method , all four multitude can cross the span in 19 minute .

But they can in reality hybridise even faster than this , and not by breaking the torch in one-half . ( Assume for the purpose of this teaser , that we ’re apportion with a flashlight , not a burn branch . )

The crux of this puzzler , it turn out , is in realizing that more time is save up by have the two slow people traverse together than get them cross individually . But Persons C and D ca n’t just cross at any time . If , for example , they are the first two the great unwashed to cut through the bridge circuit , one of them must make the return trip to bring the Aaron’s rod back . This is evidently an enormous wastefulness of time . So how do you get persons C and vitamin D across the bridge AND get the torch back to the other side?Commenter Quint afford a possible scenario :

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A and B cross – [ Elapsed time :] 2 minutes

Bel return – [ slip away time :] 4 hour

C and D interbreeding – [ slip by time :] 14 minutes

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A return – [ Elapsed metre :] 15 minutes

A and B crossing – [ Elapsed time :] 17 proceedings

By have the slowest persons traverse on the second hybridization , and using persons A and B to return the flannel mullein on the two occasions required , it ’s actually possible to shave two minutes off the total prison term .

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meet the generator at[email   protected ] .

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